If 150 J of heat is added to a system and work done by the system is 110 J, then change in internal energy will be –
Text Solution
Verified by ExpertsThe correct answer is:
B
Δ U = Δ Q – Δ W = 150 – 110 = 40 J
Δ Q = 150 J
Δ W = 110 J
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